Integrand size = 29, antiderivative size = 99 \[ \int \frac {\sec (e+f x) (a+b \sec (e+f x))}{(c+d \sec (e+f x))^2} \, dx=\frac {2 (a c-b d) \text {arctanh}\left (\frac {\sqrt {c-d} \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c+d}}\right )}{(c-d)^{3/2} (c+d)^{3/2} f}+\frac {(b c-a d) \tan (e+f x)}{\left (c^2-d^2\right ) f (c+d \sec (e+f x))} \]
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Time = 0.19 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.172, Rules used = {4088, 12, 3916, 2738, 214} \[ \int \frac {\sec (e+f x) (a+b \sec (e+f x))}{(c+d \sec (e+f x))^2} \, dx=\frac {2 (a c-b d) \text {arctanh}\left (\frac {\sqrt {c-d} \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c+d}}\right )}{f (c-d)^{3/2} (c+d)^{3/2}}+\frac {(b c-a d) \tan (e+f x)}{f \left (c^2-d^2\right ) (c+d \sec (e+f x))} \]
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Rule 12
Rule 214
Rule 2738
Rule 3916
Rule 4088
Rubi steps \begin{align*} \text {integral}& = \frac {(b c-a d) \tan (e+f x)}{\left (c^2-d^2\right ) f (c+d \sec (e+f x))}+\frac {\int \frac {(-a c+b d) \sec (e+f x)}{c+d \sec (e+f x)} \, dx}{-c^2+d^2} \\ & = \frac {(b c-a d) \tan (e+f x)}{\left (c^2-d^2\right ) f (c+d \sec (e+f x))}+\frac {(a c-b d) \int \frac {\sec (e+f x)}{c+d \sec (e+f x)} \, dx}{c^2-d^2} \\ & = \frac {(b c-a d) \tan (e+f x)}{\left (c^2-d^2\right ) f (c+d \sec (e+f x))}+\frac {(a c-b d) \int \frac {1}{1+\frac {c \cos (e+f x)}{d}} \, dx}{d \left (c^2-d^2\right )} \\ & = \frac {(b c-a d) \tan (e+f x)}{\left (c^2-d^2\right ) f (c+d \sec (e+f x))}+\frac {(2 (a c-b d)) \text {Subst}\left (\int \frac {1}{1+\frac {c}{d}+\left (1-\frac {c}{d}\right ) x^2} \, dx,x,\tan \left (\frac {1}{2} (e+f x)\right )\right )}{d \left (c^2-d^2\right ) f} \\ & = \frac {2 (a c-b d) \text {arctanh}\left (\frac {\sqrt {c-d} \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c+d}}\right )}{(c-d)^{3/2} (c+d)^{3/2} f}+\frac {(b c-a d) \tan (e+f x)}{\left (c^2-d^2\right ) f (c+d \sec (e+f x))} \\ \end{align*}
Time = 0.43 (sec) , antiderivative size = 97, normalized size of antiderivative = 0.98 \[ \int \frac {\sec (e+f x) (a+b \sec (e+f x))}{(c+d \sec (e+f x))^2} \, dx=\frac {-\frac {2 (a c-b d) \text {arctanh}\left (\frac {(-c+d) \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c^2-d^2}}\right )}{\left (c^2-d^2\right )^{3/2}}+\frac {(b c-a d) \sin (e+f x)}{(c-d) (c+d) (d+c \cos (e+f x))}}{f} \]
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Time = 0.77 (sec) , antiderivative size = 132, normalized size of antiderivative = 1.33
method | result | size |
derivativedivides | \(\frac {\frac {2 \left (a d -b c \right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{\left (c^{2}-d^{2}\right ) \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{2} c -\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{2} d -c -d \right )}+\frac {2 \left (a c -b d \right ) \operatorname {arctanh}\left (\frac {\left (c -d \right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{\sqrt {\left (c +d \right ) \left (c -d \right )}}\right )}{\left (c +d \right ) \left (c -d \right ) \sqrt {\left (c +d \right ) \left (c -d \right )}}}{f}\) | \(132\) |
default | \(\frac {\frac {2 \left (a d -b c \right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{\left (c^{2}-d^{2}\right ) \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{2} c -\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{2} d -c -d \right )}+\frac {2 \left (a c -b d \right ) \operatorname {arctanh}\left (\frac {\left (c -d \right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{\sqrt {\left (c +d \right ) \left (c -d \right )}}\right )}{\left (c +d \right ) \left (c -d \right ) \sqrt {\left (c +d \right ) \left (c -d \right )}}}{f}\) | \(132\) |
risch | \(\frac {2 i \left (-a d +b c \right ) \left (d \,{\mathrm e}^{i \left (f x +e \right )}+c \right )}{c \left (c^{2}-d^{2}\right ) f \left ({\mathrm e}^{2 i \left (f x +e \right )} c +2 d \,{\mathrm e}^{i \left (f x +e \right )}+c \right )}+\frac {\ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c^{2}-i d^{2}+\sqrt {c^{2}-d^{2}}\, d}{\sqrt {c^{2}-d^{2}}\, c}\right ) a c}{\sqrt {c^{2}-d^{2}}\, \left (c +d \right ) \left (c -d \right ) f}-\frac {\ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c^{2}-i d^{2}+\sqrt {c^{2}-d^{2}}\, d}{\sqrt {c^{2}-d^{2}}\, c}\right ) b d}{\sqrt {c^{2}-d^{2}}\, \left (c +d \right ) \left (c -d \right ) f}-\frac {\ln \left ({\mathrm e}^{i \left (f x +e \right )}-\frac {i c^{2}-i d^{2}-\sqrt {c^{2}-d^{2}}\, d}{\sqrt {c^{2}-d^{2}}\, c}\right ) a c}{\sqrt {c^{2}-d^{2}}\, \left (c +d \right ) \left (c -d \right ) f}+\frac {\ln \left ({\mathrm e}^{i \left (f x +e \right )}-\frac {i c^{2}-i d^{2}-\sqrt {c^{2}-d^{2}}\, d}{\sqrt {c^{2}-d^{2}}\, c}\right ) b d}{\sqrt {c^{2}-d^{2}}\, \left (c +d \right ) \left (c -d \right ) f}\) | \(400\) |
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Time = 0.31 (sec) , antiderivative size = 389, normalized size of antiderivative = 3.93 \[ \int \frac {\sec (e+f x) (a+b \sec (e+f x))}{(c+d \sec (e+f x))^2} \, dx=\left [\frac {{\left (a c d - b d^{2} + {\left (a c^{2} - b c d\right )} \cos \left (f x + e\right )\right )} \sqrt {c^{2} - d^{2}} \log \left (\frac {2 \, c d \cos \left (f x + e\right ) - {\left (c^{2} - 2 \, d^{2}\right )} \cos \left (f x + e\right )^{2} + 2 \, \sqrt {c^{2} - d^{2}} {\left (d \cos \left (f x + e\right ) + c\right )} \sin \left (f x + e\right ) + 2 \, c^{2} - d^{2}}{c^{2} \cos \left (f x + e\right )^{2} + 2 \, c d \cos \left (f x + e\right ) + d^{2}}\right ) + 2 \, {\left (b c^{3} - a c^{2} d - b c d^{2} + a d^{3}\right )} \sin \left (f x + e\right )}{2 \, {\left ({\left (c^{5} - 2 \, c^{3} d^{2} + c d^{4}\right )} f \cos \left (f x + e\right ) + {\left (c^{4} d - 2 \, c^{2} d^{3} + d^{5}\right )} f\right )}}, \frac {{\left (a c d - b d^{2} + {\left (a c^{2} - b c d\right )} \cos \left (f x + e\right )\right )} \sqrt {-c^{2} + d^{2}} \arctan \left (-\frac {\sqrt {-c^{2} + d^{2}} {\left (d \cos \left (f x + e\right ) + c\right )}}{{\left (c^{2} - d^{2}\right )} \sin \left (f x + e\right )}\right ) + {\left (b c^{3} - a c^{2} d - b c d^{2} + a d^{3}\right )} \sin \left (f x + e\right )}{{\left (c^{5} - 2 \, c^{3} d^{2} + c d^{4}\right )} f \cos \left (f x + e\right ) + {\left (c^{4} d - 2 \, c^{2} d^{3} + d^{5}\right )} f}\right ] \]
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\[ \int \frac {\sec (e+f x) (a+b \sec (e+f x))}{(c+d \sec (e+f x))^2} \, dx=\int \frac {\left (a + b \sec {\left (e + f x \right )}\right ) \sec {\left (e + f x \right )}}{\left (c + d \sec {\left (e + f x \right )}\right )^{2}}\, dx \]
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Exception generated. \[ \int \frac {\sec (e+f x) (a+b \sec (e+f x))}{(c+d \sec (e+f x))^2} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.31 (sec) , antiderivative size = 172, normalized size of antiderivative = 1.74 \[ \int \frac {\sec (e+f x) (a+b \sec (e+f x))}{(c+d \sec (e+f x))^2} \, dx=-\frac {2 \, {\left (\frac {{\left (\pi \left \lfloor \frac {f x + e}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (2 \, c - 2 \, d\right ) + \arctan \left (\frac {c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )}{\sqrt {-c^{2} + d^{2}}}\right )\right )} {\left (a c - b d\right )}}{{\left (c^{2} - d^{2}\right )} \sqrt {-c^{2} + d^{2}}} + \frac {b c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - a d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )}{{\left (c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - c - d\right )} {\left (c^{2} - d^{2}\right )}}\right )}}{f} \]
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Time = 13.88 (sec) , antiderivative size = 106, normalized size of antiderivative = 1.07 \[ \int \frac {\sec (e+f x) (a+b \sec (e+f x))}{(c+d \sec (e+f x))^2} \, dx=\frac {2\,\mathrm {atanh}\left (\frac {\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\sqrt {c-d}}{\sqrt {c+d}}\right )\,\left (a\,c-b\,d\right )}{f\,{\left (c+d\right )}^{3/2}\,{\left (c-d\right )}^{3/2}}-\frac {2\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (a\,d-b\,c\right )}{f\,\left (c+d\right )\,\left (c-d\right )\,\left (\left (d-c\right )\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2+c+d\right )} \]
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